Norman Sword Posted November 6, 2017 Report Share Posted November 6, 2017 (edited) Expanding on the theme ; The value in (ix+$05) is only used locally X9278 ;>>9278 LD (IX+$05),$00 LD BC,$700 ;-1 B=7 C=0 X927C LD A,(HL);>>927D AND $07 ;>>927F CP $07 INC A ;-2 AND B ;-3 X9281 JR NZ,L_9286 ;>>9283 DEC (IX+$05) DEC C ;-5 L_9286 LD A,(HL);>>9287 OR $07 OR B ;-6 X9289 LD (HL),AX928A INC DE X928B LD A,(DE)X928C LD H,A X928D DEC HX928E LD A,(IX+$06) LD B,A ;-5X9291 LD (HL),AX9292 INC H X9293 LD A,(HL) ;>>9294 AND (IX+$05) AND C ;-7 X9297 JP NZ,$90B7 ;>>>>> kill Willy X929A LD (HL),$FF X929C INC H ;>>X929D LD A,(IX+$06) ;>>X92A0 LD (HL),A LD (HL),B ;-9X92A1 JP $93B3 Edited November 7, 2017 by Norman Sword Spider and IRF 2 Quote Link to comment Share on other sites More sharing options...
IRF Posted November 8, 2017 Report Share Posted November 8, 2017 ;>>X929D LD A,(IX+$06) ;>>X92A0 LD (HL),A LD (HL),B ;-9 I believe that the running total of saved bytes at that point should be 10, rather than 9? I think it could also be done without using B (the net byte-saving would be the same). From #928E (rejigged code shown in bold): LD A,(IX+$06) LD (HL),A INC H INC H LD (HL),A DEC H LD A,(HL) AND C JP NZ,#90B7 ;>>>>> kill Willy LD (HL),#FF JP #93B3 The above arrangement would also mean that the arrow is drawn in its entirety at the moment when it hits Willy (whereas in the original code, only the top pixel-row is drawn at the point of death). Spider 1 Quote Link to comment Share on other sites More sharing options...
IRF Posted November 8, 2017 Report Share Posted November 8, 2017 Error in Norman Sword's post about the conveyor animation?: http://jswmm.co.uk/topic/185-free-space-and-code-optimisation-in-jsw/page-8?do=findComment&comment=6105 L38163 LD A,(HL) ; Copy a pixel row of the conveyor tile to A Shouldn't that be a LD A,(DE) in the context of the revised logic? Quote Link to comment Share on other sites More sharing options...
Norman Sword Posted November 8, 2017 Report Share Posted November 8, 2017 (edited) I believe that the running total of saved bytes at that point should be 10, rather than 9? I think it could also be done without using B (the net byte-saving would be the same). From #928E (rejigged code shown in bold): LD A,(IX+$06) LD (HL),A INC H INC H LD (HL),A DEC H LD A,(HL) AND C JP NZ,#90B7 ;>>>>> kill Willy LD (HL),#FF JP #93B3 The above arrangement would also mean that the arrow is drawn in its entirety at the moment when it hits Willy (whereas in the original code, only the top pixel-row is drawn at the point of death). If the code had been written as Ld a,(ix+$06) ld (hl),a inc h inc h ld (hl),a dec h ld a,(hl) and c ld (hl),$ff jp nz,#90b5 ;>>>> kill willy jp #93b3 Then it might have been a valid point on drawing the arrow Otherwise you have returned and not drawn the arrow shaft. Byte code is purely a guide. (the count is indicating a trend- nothing more) Edited November 8, 2017 by Norman Sword Spider and IRF 2 Quote Link to comment Share on other sites More sharing options...
IRF Posted November 8, 2017 Report Share Posted November 8, 2017 (edited) Yes, that's what I meant. (Draw the arrow shaft first before reacting to the Zero Flag.)In relation to the byte count, I merely meant to point out that you did yourself a disservice! Edited November 17, 2017 by IRF Quote Link to comment Share on other sites More sharing options...
Norman Sword Posted November 8, 2017 Report Share Posted November 8, 2017 (edited) Error in Norman Sword's post about the conveyor animation?: http://jswmm.co.uk/topic/185-free-space-and-code-optimisation-in-jsw/page-8?do=findComment&comment=6105 Shouldn't that be a LD A,(DE) in the context of the revised logic? The listings I have provided are created ad hoc. ; the version I have currently looks like this. Next week it might be changed again JR Z,TOTHER EX DE,HL TOTHER LD A,(DE) :>>>>>> the opcode in question LD C,(HL) RLC A RRC C CON_DO LD (DE),A LD (HL),C INC E INC L DJNZ CON_DO RET But I will go back and change the opcode... The link back to the code, does not provide any means of editing the code. Edited November 8, 2017 by Norman Sword Spider and IRF 2 Quote Link to comment Share on other sites More sharing options...
IRF Posted November 8, 2017 Report Share Posted November 8, 2017 That looks like it only rotates the pertinent pair of graphic bytes once per time-frame? Meaning that the Master Bed would visible animate? (Whereas it doesn't in the original game, because the pixel pattern is such that two rotations, in either direction, leave the value of the bytes unchanged.) Talking of making tweaks to the original arrangement, adjusting the number of INC H commands will allow a different pixel-row of the conveyor, at an arbitrary depth beneath the top pixel-row, to act as the counter-rotating element of the conveyor. Spider 1 Quote Link to comment Share on other sites More sharing options...
IRF Posted November 8, 2017 Report Share Posted November 8, 2017 The link back to the code, does not provide any means of editing the code. Don't worry, it's here on record now. Thank you for the clarification (and for the original optimisation!) Spider 1 Quote Link to comment Share on other sites More sharing options...
Norman Sword Posted November 8, 2017 Report Share Posted November 8, 2017 (edited) The reason I only rotate once is simply because I do not like the original animation. When willy or a sprite is animated on a conveyor, the speed the conveyor moves is exactly the same speed as willy moves. (or a standard horizontally moving sprite) Simple logic dictates that if the conveyor is moving in the same direction as willy and at the same speed then the conveyor is static below willies feet. It then follows that willy should not be animated. He should stay in the same frame and move graciously and serenely along the conveyor without moving a limb. The game does not provide that kind of animation, so my compromise is to move the conveyor at a slower speed to justify the animation. The speed change is also linked to the direction byte. (not listed in the code because it is not part of the original) but in my versions, the direction byte also stores animation status bits. The bits switch on/off animation. e.g. In this manner/style (done by me, in various edits) bit 5 no animation of the conveyor. Return immediately. bit 6 no lower animation of the conveyor . point high of register pair to "0" bit 7 reverse animate the conveyor (reverse animate, just to confuse) .xor bit with direction bit before testing By testing a bit in the direction byte. Either HL or DE can be set to point to the ROM. By setting "D" or "H" to 0. This allows the following code to stay the same. But the registers pointing to the ROM will stop the appropriate animation from being shown. The code as used by Matthew can easily be modified to use a consistent check on the direction byte. e.g. ignore all the other bits, which then become available to use. . Edited November 9, 2017 by Norman Sword Spider and IRF 2 Quote Link to comment Share on other sites More sharing options...
Norman Sword Posted November 9, 2017 Report Share Posted November 9, 2017 (edited) Byte saving. This is something that Matthew does as part of the code to move down the screen from raster line to raster line. ld a,l ;line 1add a,$20 ; 2ld l,a ; 3 and $e0 : 4 ret nz ; or jr nz (depending on version) I just wonder why the opcode -and $e0- is used on line 4. The addition on line 2 - add a,$20 - has set the carry flag for all the conditions that are wanted. The code should be. ld a,l ;line 1add a,$20 ; 2ld l,a ; 3ret c ; or jr c (depending on version) This save two bytes. Since various mods have been used around this area, The exact condition Carry or no carry, will depend on what else is happening around this code area. Edited November 9, 2017 by Norman Sword Spider and IRF 2 Quote Link to comment Share on other sites More sharing options...
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